FizzBuzz

https://codenewbiesite.files.wordpress.com/2017/01/fizzbuzz.png?w=660 source After coming across a post from @reggaemuffin where he hosted a coding challenge where I submitted a pretty amateur solution in Python he insisted that I make a separate post where I could explain my thinking process and the logic behind it. It's not a very difficult challenge but it's a pretty nice one to try for the sake of learning and potentially teaching others. So here's the rules to the challenge:

![Screenshot from 2017-08-18 11-28-21.png](https://steemitimages.com/DQmNXAUVKft1exoDoNEaJktFfUzcjnZYqp8LXGQTRqJx1iy/Screenshot%20from%202017-08-18%2011-28-21.png)

The fist thing that should pop up into your head when you hear the word 'multiples' is the **modulo operator(%)**. So what exactly is the modulo operator I hear you ask? Well thanks for asking. We can use the modulo operator to return the remainder of a division. For example, 8%5 will give us an answer of 3 since 5 goes into 8 once and 3 is left which is the remainder. When one number is fully dividable by another a remainder of 0 is left. This way we can determine if a number is a multiple of another by dividing the two numbers using the modulo operator and getting a remainder of 0. Amazing right? Not really but it's perfect for this challenge so we'll be using it. Let's get to the the code. ![code.png](https://steemitimages.com/DQmRt1RVgZM2vghsagR6RggXdHap6YYqfCNf6VRxfkzf36Y/code.png) For the sake of explaining I made my solution a little longer and more manageable than this gloriously ugly one line solution I found online.

Code Explanation

On **line 1** we start by creating our function that will do all the heavy work for us. We add a parameter for 'n' which will be used as a variable storing the number that we want do some calculations with in order to determine if its a multiple of 3, 5 or both. On **line 3** we start our try-except which we'll use to handle value errors such as when a string is passed to our function since we can't divide a word by n dumber. duh From **lines 4 - 11** we have all of our conditional statements which will help us determine if we should either print 'Fizz', 'Buzz', 'FizzBuzz' or if you should just return the number. We check if n is a multiple of 5 and 3 **first** otherwise if we checked if n was a multiple of 3 **or** 5 first there's a definite change that we'll miss a FizzBuzz since if we find a multiple of 3 **or** 5 first the statement will result in **true** and the rest of the statements will be skipped. We store our word in a variable called test which we return on **line 13**. On **line 15 and 16** we return an error message in case someone tried to send a string or any other datatype with which we can not do calculations with. On **lines 18 - 20** we define our main function which will be called by the function on **lines 22 and 23**. In our main function we have a for loop which will call our ````fizzbuzz(n) ```` function 100 times passing it an integer from 0 - 100 as it loops through the integer range of 0 -100 and print out the returned text variable that contains our words or the integer in case it's not a multiple of 3 or 5.

Please Note: This is obviously not the shortest most efficient solution out there. I wrote it this way in order to help show people the thinking process as well as the logic behind solving a problem like this. I hope you learned something :)

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